Удаление первых n строк текстового файла

@echo off
set n=10
set File_Src=textfile_in.txt
set file_Dest=textfile_out.txt
 
set /A n+=1
more /+%n% < "%File_Src%" > "%file_Dest%"

@echo off
setlocal enableextensions enabledelayedexpansion
set n=10
set File_Src=textfile_in.txt
set file_Dest=textfile_out.txt
 
cd.>"%file_Dest%"
for /f "usebackq delims=" %%a in ("%File_Src%") do (
  set /A C+=1
  if !C!==%n% echo %%a>>"%file_Dest%"
  echo %%a>>"%file_Dest%"
)

more +%n% < "%File_Src%" > "%file_Dest%"

set file_in=a.txt
set file_out=total.txt

@echo off
rem переход в папку бат файла - чтоб не указывать полный путь
cd /d %~dp0
cls
rem ввести имя файла
set name=1.txt
rem ввести номер строки
set /p number=ENTER NUMBER STRING:
for /f "usebackq  delims=" %%i in (`find /n /v "" %name% ^| find "[%number%]"`) do (set str=%%i)
rem пропуск лишних символов в начале строки
for /f "delims=] tokens=2" %%i in ("%str%") do (set str=%%i)
echo %str%
setlocal enabledelayedexpansion
set file_in=1.txt
set file_out=result.txt
if exist "%file_out%" del /f /q "%file_out%"
>nul find /i /v "%number%" < "%file_in%" >> "%file_out%"
echo %str%>>result.txt
echo Thats all
echo.
set /p st=DO YOU WANT TO OPEN TEXT? [y\n]:
if "%st%"=="y" start result.txt
exit

@echo off
setlocal enabledelayedexpansion
cd /d %~dp0
set file=1.txt
set out=2.txt
set counter=0
for /f "usebackq tokens=*" %%A IN ("%file%") DO (
 set /a counter=!counter!+1
 echo.!counter!^|%%A
)
set counter=0
:n
set /p n=Enter string number     ^>
if "%n%"=="" goto n
(for /f "usebackq tokens=*" %%A IN ("%file%") DO (
 set /a counter=!counter!+1
 if !counter!==!n! (echo.%%A)
 echo.%%A
))>"%out%"
pause>nul
exit /b

@echo off
set n=10
set File_Src=1.txt
set file_Dest=2.txt
 
more +%n% < "%File_Src%" > "%file_Dest%"

start x:\1.txt
exit

@echo off
setlocal enableextensions enabledelayedexpansion
set n=10
set File_Src=1.txt
set file_Dest=2.txt
 
more +%n% < "%File_Src%" > "%file_Dest%"