Fn(string s) - в массив функций - C++ - Ответ 10401145

#include <functional>
#include <iostream>
#include <string>
#include <vector>
 
size_t f1(const std::string &s)
{
    return s.length();
}
 
size_t f2(const std::string &s)
{
    return s.length() * 2;
}
 
size_t f3(const std::string &s)
{
    return s.length() * 3;
}
 
int main()
{
    std::vector<std::function<size_t(const std::string &)>> fns = {f1, f2, f3};
    for (const auto &fn : fns)
        std::cout << fn("ololo") << " ";
}

#include <iostream>
#include <string>
#include <vector>
 
size_t f1(const std::string &s)
{
    return s.length();
}
 
size_t f2(const std::string &s)
{
    return s.length() * 2;
}
 
size_t f3(const std::string &s)
{
    return s.length() * 3;
}
 
int main()
{
    std::vector<size_t(*)(const std::string &)> fns;
    fns.push_back(f1);
    fns.push_back(f2);
    fns.push_back(f3);
    for (std::vector<size_t(*)(const std::string &)>::const_iterator cit = fns.begin(); cit != fns.end(); ++cit)
        std::cout << (*cit)("ololo") << " ";
}