Добавлено через 43 секунды
void *memmove(void *dest, const void *src, size_t n);
The memmove() function copies n bytes from memory area src to memory area dest. The memory areas may overlap: copying
takes place as though the bytes in src are first copied into a temporary array that does not overlap src or dest, and the
bytes are then copied from the temporary array to dest.
The memmove() function returns a pointer to dest.
SVr4, 4.3BSD, C89, C99, POSIX.1-2001.