Арабские в римские - C++ - Ответ 365055

#include <stdio.h>
#include <stdlib.h>
#include <string.h> 
 
#define    NUMS    13
 
char* to_roman( unsigned int num, char* buff )
{
    int p = NUMS;
    unsigned int a_num[NUMS] = {1,4,5,9,10,40,50,90,100,400,500,900,1000};
    char* r_str[NUMS] = {"I","IV","V","IX","X","XL","L","XC","C","CD","D","CM","M"};
 
    *buff = '\0';
    while (p--)
    while (num >= a_num[p])
    {
        num -= a_num[p];
        strcat( buff, r_str[p] );
    }
 
    return buff;
}
 
int main( void )
{
    char* roman;
    unsigned int arabian = 3451;
 
    roman = (char*)malloc(256);
    printf( "%i: %s\n", arabian, to_roman( arabian, roman ));
    free( roman );
 
    return 0;
}

printf("Vvedite chislo: \n");
    scanf("%d", &arabian);
    if(arabian > 1 || arabian < 3889);
    { 
    roman = (char*)malloc(256);
    printf( "%i: %s\n", arabian, to_roman( arabian, roman ));
    }