Поразрядные операции (Запрограммировать изменение в с++ двухбайтного числа) - C++ - Ответ 4432717

#include <iostream>
 
template <typename T>
inline int is_bit_set(const T& value, size_t pos)
  {
  return (value & (1 << pos)) != 0;
  }
 
template <typename T>
void print_by_bites(const T& value)
  {
  int last = sizeof(T) * 8 - 1;
  for (size_t i = 0; i < last; ++i)
    std::cout << is_bit_set(value, i);
  std::cout << is_bit_set(value, last) << std::endl;
  }
 
struct Byte
  {
  unsigned _0 : 1;
  unsigned _1 : 1;
  unsigned _2 : 1;
  unsigned _3 : 1;
  unsigned _4 : 1;
  unsigned _5 : 1;
  unsigned _6 : 1;
  unsigned _7 : 1;
  };
 
union Short
  {
  Byte first;
  Byte second;
 
  short value;
  };
 
int main()
  {
  std::cout << "first method" << std::endl;
 
  short *word_1 = new short(0);
  
  for (int i = 0; i < sizeof(short) * 8; ++i)
    {
    *word_1 |= (1 << i);
    print_by_bites(*word_1);
    }
 
  for (int i = 0; i < sizeof(short) * 8; ++i)
    {
    *word_1 &= ~(1 << i);
    print_by_bites(*word_1);
    }
  delete word_1;
 
  std::cout << "second method" << std::endl;
  Short *word_2 = new Short;
  memset(word_2, 0, sizeof(Short)); //clrear
 
  /*it's 3*/
  word_2->first._0 = 1;
  word_2->first._1 = 1;
 
  std::cout << "value of word_2: " << word_2->value << std::endl;
  memset(word_2, 0, sizeof(Short)); //clrear
 
  /*it's 8*/
  word_2->first._3 = 1;
  std::cout << "value of word_2: " << word_2->value << std::endl;
 
  delete word_2;
 
  std::cin.get();
  return 0;
  }