Перегрузка оператора присваивания - C++ - Ответ 5778740

#include "h.h"
 
Cow::Cow()
{
    cout << "Вызван конструктор" << endl;
    chobby = NULL;
    weight = 0;
}
 
Cow::Cow(const char* nm, const char* ho, double wt)
{
    cout << "Вызван конструктор" << endl;
    strncpy(name,nm,20);
    chobby = new char[strlen(ho)+1];
    strcpy(chobby,ho);
    weight = wt;
}
 
Cow::Cow(const Cow & c)
{
    cout << "Вызван конструктор" << endl;
    strncpy(name,c.name,20);
    chobby = new char[strlen(c.chobby)+1];
    strcpy(chobby,c.chobby);
    weight = c.weight;
}
 
Cow::~Cow()
{
    cout << "Вызван деструктор:" << endl;
    delete [] chobby;
}
 
Cow & Cow::operator=(const Cow & c)
{
    cout << "Вызвана операция присваивания" << endl;
    if (&c == this)
        return *this;
    delete [] chobby;
    strncpy(name,c.name,20);
    chobby = new char[strlen(c.chobby)+1];
    strcpy(chobby,c.chobby);
    return *this;
}
 
void Cow::ShowCow() const
{
    cout << "name: " << name << endl;
    cout << "chobby: " << chobby << endl;
    cout << "weight: " << weight << endl;
}

#include <iostream>
#include <Windows.h>
#include "h.h"
 
using namespace std;
 
#define rus setlocale(0,"rus");SetConsoleCP(1251);SetConsoleOutputCP(1251);
 
int main()
{
    rus;
    cout << "Obj1:\n";
    Cow* Obj1 = new Cow;
    cout << "Obj2:\n";
    Cow* Obj2 = new Cow("ABC","DEF",582.1);
    cout << "Obj3:\n";
    Cow* Obj3 = new Cow(*Obj2);
    cout << "Obj4:\n";
    Cow* Obj4 = Obj1;
 
    Obj1->ShowCow();
    Obj2->ShowCow();
    Obj3->ShowCow();
    Obj4->ShowCow();
 
    Obj1->~Cow();
    Obj2->~Cow();
    Obj3->~Cow();
    Obj4->~Cow();
}