Получить из строки отдельно фамилию, имя, отчество, возраст и номер телефона - C++ - Ответ 6655098

#include "conio.h"
#include <iostream>
#include <regex>
#include <string>
 
using namespace std;
 
enum SubString{ ss_surname, ss_name, ss_patronymic, ss_age, ss_phone, ss_last };
enum { max_str_len = 256 };
 
bool SplitString( const char *inputString, char *outputSubStrings )
{
  regex expression("([^\\s]+)"); 
  cregex_token_iterator i(inputString, inputString+strlen(inputString), expression);
  int count = 0;
 
  for( ; i!=cregex_token_iterator(), count < ss_last; i++, count++ )
    strcpy( outputSubStrings+count*max_str_len, i->str().c_str() );
 
  return count == ss_last;
}
 
int main()
{
    const char *inputString = "ivanov ivan ivanovich 20 1111111";
    char outputSubStrings[ss_last][max_str_len];    
    
    cout << "Parsing line:" << inputString << endl;
 
    if( SplitString(inputString,*outputSubStrings) == false ) 
      cout << "Some error happened wihle parsing line..." << endl;
    else 
    {
      cout << "Surname    "  << outputSubStrings[ss_surname]    << endl;
      cout << "Name       "  << outputSubStrings[ss_name]       << endl;
      cout << "Patronymic "  << outputSubStrings[ss_patronymic] << endl;
      cout << "Age        "  << outputSubStrings[ss_age]        << endl;
      cout << "Phone      "  << outputSubStrings[ss_phone]      << endl;
    }
    getch();
}