Как спарсить результат выдачи Google

import urllib.request
 
def get_HTML(url):
    responce = urllib.request.urlopen(url)
    return responce.read()
 
site = 'https://www.google.com/search?q=777&ie=utf-8&oe=utf-8'
print(get_HTML(site))

Traceback (most recent call last):
  File "C:/Users/Алексей/PycharmProjects/untitled1/main.py", line 18, in <module>
    main()
  File "C:/Users/Алексей/PycharmProjects/untitled1/main.py", line 15, in main
    print(get_HTML(site))
  File "C:/Users/Алексей/PycharmProjects/untitled1/main.py", line 5, in get_HTML
    responce = urllib.request.urlopen(url)
  File "C:\Users\Алексей\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 162, in urlopen
    return opener.open(url, data, timeout)
  File "C:\Users\Алексей\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 471, in open
    response = meth(req, response)
  File "C:\Users\Алексей\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 581, in http_response
    'http', request, response, code, msg, hdrs)
  File "C:\Users\Алексей\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 503, in error
    result = self._call_chain(*args)
  File "C:\Users\Алексей\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 443, in _call_chain
    result = func(*args)
  File "C:\Users\Алексей\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 686, in http_error_302
    return self.parent.open(new, timeout=req.timeout)
  File "C:\Users\Алексей\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 471, in open
    response = meth(req, response)
  File "C:\Users\Алексей\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 581, in http_response
    'http', request, response, code, msg, hdrs)
  File "C:\Users\Алексей\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 509, in error
    return self._call_chain(*args)
  File "C:\Users\Алексей\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 443, in _call_chain
    result = func(*args)
  File "C:\Users\Алексей\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 589, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 403: Forbidden

    site = 'https://www.google.ru/#q=s&newwindow=1&start=0'
    page = None
    r = requests.get(site)
    page = r.text
    print(page)

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
 
search_engine = "http://www.google.ru"
search_string = "Путин Владимир Владимирович" #:)
 
browser = webdriver.Firefox()
browser.get(search_engine)
element = browser.find_element_by_name('q')
element.send_keys(search_string + ' wiki' + Keys.RETURN)
#waiting for loading SERP
browser.implicitly_wait(5)
all_links = browser.find_elements_by_css_selector('a:link')
hrefs = []
hrefs = [x.get_attribute('href') for x in all_links if x.get_attribute('href') not in hrefs]

   
import requests
 
 site = 'https://www.google.ru/#q=s&newwindow=1&start=0'
    page = None
    r = requests.get(site)
    page = r.text
    print(page)

  File "C:/Users/Алексей/PycharmProjects/untitled1/selenium.py", line 5
SyntaxError: Non-UTF-8 code starting with '\xcf' in file C:/Users/Алексей/PycharmProjects/untitled1/selenium.py on line 5, but no encoding declared; see [url]http://python.org/dev/peps/pep-0263/[/url] for details

search_engine = "http://www.google.ru"
search_string = "Путин Владимир Владимирович" #:)

hrefs = []
hrefs = [x.get_attribute('href') for x in all_links if x.get_attribute('href') not in hrefs]

search_string = "что-то найти..."
element = browser.find_element_by_name('q')
element.send_keys(search_string + Keys.RETURN)

all_links = browser.find_elements_by_css_selector('a:link')