Как спарсить номер телефона из Avito?

import requests
import re
headers = {'User-Agent' : 'Mozilla/5.0 (Windows; U; Windows NT 5.1; ru; rv:1.9.0.13) Gecko/2009073022 Firefox/3.0.13'}
r = requests.get('http://m.avito.ru/item/160974735', headers=headers)
text = r.text
 
LinkWithTrash = re.search(r'showPhone\(event\)\"\shref=\".+\"', text).group() #Ссылка с лишними тегами
NotFullLink = LinkWithTrash[24:-61] #Часть ссылки
FullLink = 'http://m.avito.ru' + NotFullLink #Полная ссылка
print FullLink
p = requests.get(FullLink, cookies=r.cookies, headers=headers) #Новый запрос спрошлыми кукисами 
print p.text # Почему-то в номом исходном коде нет телефона

from twisted.internet import reactor
from twisted.web.client import getPage
 
def callback(page):
    # do smth with page - it will be a string
    if reactor.running:
        reactor.stop()
 
def main():
    url = 'http://m.avito.ru/item/160974735'
    getPage(url).addCallback(callback)
    reactor.run()
 
if __name__ == '__main__':
    main()

from lxml import html
 
def callback(page):
    doc = html.document_fromstring(page)
    href = doc.xpath("//a[@id='showPhoneBtn']/@href")[0]

def get_phone(page):
    # с помощью xpath вытаскиваем телефон
    doc = html.document_fromstring(page)
    phone = doc.xpath("//li[@class='para m_item_phone']/a/text()")[0]
 
    if reactor.running:
        reactor.stop()

import requests
from urllib.parse import urljoin
 
from lxml.html import fromstring
 
def getPhone(url):
    headers = {'User-Agent' : 'Mozilla/5.0 (Windows; U; Windows NT 5.1; ru; rv:1.9.0.13) Gecko/2009073022 Firefox/3.0.13'}
 
    session = requests.session()
    resp = session.get(url, headers=headers)
 
    html = fromstring(resp.content)
    href = html.xpath("//a[@id='showPhoneBtn']/@href")[0]
 
    url = urljoin(resp.url, href)
    resp = session.get(url)
 
    html = fromstring(resp.content)
    phone = html.xpath("//li[@class='para m_item_phone']/a/text()")[0]
 
    return phone

import lxml.html
from urllib import request
import requests
from urllib.parse import urljoin
from lxml.html import fromstring
url = "http://rp5.ru/%D0%9F%D0%BE%D0%B3%D0%BE%D0%B4%D0%B0_%D0%B2_%D0%9A%D1%80%D0%B0%D1%81%D0%BD%D0%BE%D0%B4%D0%B0%D1%80%D0%B5,_%D0%9A%D1%80%D0%B0%D1%81%D0%BD%D0%BE%D0%B4%D0%B0%D1%80%D1%81%D0%BA%D0%B8%D0%B9_%D0%BA%D1%80%D0%B0%D0%B9"
 
http_proxy = "http://Zud_AD:2231s@10.5.45.250:3128"
 
proxyDict = { 
             
              "http" : http_proxy
              
            }
 
r = requests.get(url,  proxies=proxyDict)
 
html = fromstring(r.content)
temp= html.xpath("//div[@class='t_0']/a/text()")[0]

Traceback (most recent call last):
  File "C:/Python32/xd", line 18, in <module>
    html = fromstring(r.content)
  File "C:\Python32\lib\site-packages\lxml\html\__init__.py", line 630, in fromstring
    if start.startswith('<html') or start.startswith('<!doctype'):
TypeError: expected an object with the buffer interface