Вывести содержимое таблицы MySQL в dataGridView

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using MySql.Data.MySqlClient;
 
namespace WindowsFormsApplication25
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }
 
        private void button1_Click(object sender, EventArgs e)
        {
 
            InitializeComponent();
 
            string Connect = "Database = data; Data Source = 127.0.0.1; User Id = data; Password = 1234";
            MySqlConnection MyConnection = new MySqlConnection(Connect);
            MyConnection.Open();
 
            
            MySqlDataAdapter MyData = new MySqlDataAdapter();
            string MySelect = "select * from table";
            MyData.SelectCommand = new MySqlCommand(MySelect, MyConnection);
 
            DataTable table = new DataTable();
            MyData.Fill(table);
 
            BindingSource bsource = new BindingSource();
            bsource.DataSource = table;
 
            dataGridView1.DataSource = bsource;
 
            this.dataGridView1.Columns[0].Visible = false;
            
            MyConnection.Close();
 
 
 
        }
 
        private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e)
        {
 
        }
    }
}