FizzBuzz без использования "if"

// task: https://en.wikipedia.org/wiki/Fizz_buzz
// compile: g++ -Wall -Wpedantic -Werror fizz_buzz.cxx -o fizz_buzz
 
#include <iostream>
#include <string>
namespace
{
std::string solve(int num);
}
int main()
{
    for(int num = 1; num <= 100; ++num)
    {
        std::cout << solve(num) << std::endl;
    }
    return 0;
}
 
namespace
{
 
using functor = std::string(*)(int);
 
std::string number(int num)
{
    return std::to_string(num);
}
 
std::string fizz(int)
{
    return "Fizz";
}
 
std::string buzz(int)
{
    return "Buzz";
}
std::string fizz_buzz(int)
{
    return "FizzBuzz";
}
 
functor solvers[2][2] = {
    { &number, &buzz      },
    { &fizz  , &fizz_buzz }
};
 
std::string solve(int num)
{
    return (solvers[0 == num % 3][0 == num % 5])(num);
}
}