Массивы строк. По имени абонента найти его номер

#include <cstring>
using namespace std;
 
int main(){
 
    int i;
    char str[80];
    char numbers[10][80] ={
    "Tom", "555-3322",
    "Mery","555-8976",
    "Jon","555-1037",
    "Reychel", "555-1400",
    "Sheron", "555-8873"
    };
    
    cout << "Name: ";
    cin >> str;
    
    for (i=0;i<10;i+=2)
     if(!strcmp(str,numbers[i])){
        cout << "Phone " << numbers[i+1]<<endl;
        break;
     }
    if(i==10) cout << "Not found"<<endl;
 
return 0; 
}

!strcmp(str,numbers[i])

numbers[i]

numbers[i]

    char numbers[10][80] ={
    "Tom", "555-3322",
    "Mery","555-8976",
    "Jon","555-1037",
    "Reychel", "555-1400",
    "Sheron", "555-8873"
    };

char numbers[10][80] ={
    "Tom", "555-3322",
    "Mery","555-8976",
    "Jon","555-1037",
    "Reychel", "555-1400",
    "Sheron", "555-8873"
    };

#include <iostream>
#include <string>
#include <map>
using namespace std;
 
int main()
{
    string str;
    map<string, string> numbers;
 
    numbers["Tom"] = "555-3322";
    numbers["Mery"] = "555-8976";
 
    cout << "Name: ";
    cin >> str;
    
    cout << "Phone: ";
    if(numbers.find(str)!=numbers.end()) 
        cout << numbers[str];
    else
        cout << "not found";
 
    return 0;
}

#include <iostream>
using namespace std;
 
int main(){
    int sqrs[10][3] = {1,1,2,4,3,9};
    int sqr[10][3] = {{1,1},{2,4},{3,9}};
    
    for (int i=0; i<10;i++)
        for (int j=0;j<3;j++)
         cout <<"sqrs ["<<i<<"]"<<"["<<j<<"]="<<sqrs[i][j]<<endl;
         
         cout <<endl<<endl;
         for (int i=0; i<10;i++)
        for (int j=0;j<3;j++)
         cout <<"sqrs ["<<i<<"]"<<"["<<j<<"]="<<sqr[i][j]<<endl;
         
         
return 0;
}