Подсчитать количество слов в строке

#include <stdio.h>
#include <conio.h>
#include <string.h>
 
#define size 255
int main(){
char buf[size];
printf("input text: "); gets(buf);
unsigned int lenght = strlen(buf);
unsigned int i ;
int count = 1;
for( i = 0 ; i < lenght ; i++)if(buf[i]==' '||buf[i]=='\0')count++;
printf("count of words : %d",count);
printf("\n");
 
getch();
return 0;
}

#include <stdio.h>
#include <conio.h>
#include <string.h>
 
#define size 255
int main(){
char buf[size] = "ddddddddd\n aaaaaaa\n nrrrrr\n kkkk \n ";
 
 
unsigned int lenght = strlen(buf);
unsigned int i ;
printf("%s",buf);
printf("\n");
 
int count = 0;
for( i = 0 ; i < lenght ; i++)if(buf[i]=='\n')count++;
printf("count of str : %d",count);
printf("\n");
 
 
 
 
 
 
getch();
return 0;
}

...
#include <string.h>
...
char buf[SOME_SIZE], *p;
size_t count;
...
for ( count = 0, p = strtok(buf, " "); p != NULL; ++count, p = strtok(NULL, " ") )
  ;
printf("%d words\n", count);
...

#include <stdio.h>
#include <conio.h>
#include <string.h>
 
#define size 255
int main(){
char buf[size];
printf("input text: "); gets(buf);
unsigned int lenght = strlen(buf);
unsigned int i ;
int count = 1;
for( i = 0 ; i < lenght ; i++)if((buf[i]==' '&&buf[i+1]!=' ')||buf[i]=='\0')count++;
printf("count of words : %d",count);
printf("\n");
 
getch();
return 0;
}

#include<stdio.h>
#include<string.h>
#define SBUF 256
int main(){
    int i=0;
    char buf[SBUF];
    printf("\nEnter string\n");
    gets(buf);
    if(strtok(buf," ")!=0){
        i++;
        while(strtok(NULL," ")!=NULL){
            i++;
        }
    }
    printf("%d\n",i);
    return 0;
}