Ввести и вывести список лиц по заданному возрасту

#include <iostream>
#include <string>
#include <map>
char input(std::map<int, std::string>& coll) {
    std::string name;
    int age;
    char ch;
    std::cout << "Input name:"; std::cin >> name;
    std::cout << "Input age:";  std::cin >> age;
    coll[age] = name;
    std::cout << "Repeat input?(y/n):"; std::cin >> ch;
    return ch;
}
int main() {
    std::map<int, std::string> coll;
    int N;
    input(coll);
    while(input(coll) == 'y');
    std::cout << "Input N:"; std::cin >> N;
 
    std::map<int, std::string>::iterator end = coll.upper_bound(N);
    for(std::map<int, std::string>::iterator it = coll.begin(); it != end; ++it)     {
        std::cout << "Name: " << (*it).second << std::endl;
        std::cout << "Age:" << (*it).first << std::endl;
    }
}

std::cout << "Repeat input?(y/n):";

#include <iostream.h>
#include <string.h>
#include <conio.h>
using namespace std;
int main() 
{
    int K, N;
    cout<<"Vvedite colichesnvo family"<<endl;
    cin>>K;
    int *birthYear=new int[K];
    string *family=new string[K];
    for (int i=0;i<K;i++) 
    {
        cout <<"Vvedite family i god rogdenia"<<endl;
        cin >>family[i]>>birthYear[i];
    }
    cout<<"Vvedite minys skolko let"<<endl;
    cin>>N;
    int nowYear = 2015;
    for (int i=0;i<K;i++)
        if (nowYear-N <= birthYear[i])
        cout<<"Rezultat:  "<< family[i]<< " "<<nowYear-birthYear[i]<<endl;
    getch();       
    return 0;
}