По названию месяца вывести его порядковый номер и название времени года.

#include <iostream>
#include <map>
#include <string>
 
struct info
{
    int number;
    std::string season;
};
 
int main()
{
    std::map<std::string, info> months;
    months["January"] =  {1, "Winter"};
    months["February"] = {2, "Winter"};
    months["March"] = {3, "Spring"};
    months["April"] = {4, "Spring"};
    months["May"] = {5, "Spring"};
    months["June"] = {6, "Summer"};
    months["July"] = {7, "Summer"};
    months["August"] = {8, "Summer"};
    months["September"] = {9, "Autumn"};
    months["October"] = {10, "Autumn"};
    months["November"] = {11, "Autumun"};
    months["December"] = {12, "Winter"};
    std::string name;
    std::cin >> name;
    auto i = months.find (name);
    std::cout << i->second.number << ' ' << i->second.season << std::endl;
}

#include <iostream>
using namespace std;
const char *m[]={"dec","jan","feb","mar","apr","may","jun","jul","aug","sep","oct","nov"};
const char *s[]={"winter","spring","summer","autumn"};
int main() {
    int n;
    cout << "month: "; cin >> n;
    if (n>=1 && n<=12)
        cout << m[n%12] << ", " << s[n%12/3];
    else
        cout << "wrong month number";
    cout << endl;
}

std::map<std::string, info>::iterator i = months.find (name);

std::string name;
std::cin >> name;
std::cout << months[name].number << " " << months[name].season;