Подсчитать слова, состоящие из латинских прописных букв.

int main(int argc, char* argv[])
{
int cnt=0, i;
char *str="I can use the online Help system from the Help menu.";
for (i=1; strlen(str); i++)
 if (str[i] in ['a'..'z'])
  cnt++;
printf("Stroka = %s", str);
printf("Dlina slov = %d", cnt);
getchar();
}

if (str[i] in ['a'..'z'])

//---------------------------------------------------------------------------
#include <stdio.h>
#include <string.h>
#pragma hdrstop
 
//---------------------------------------------------------------------------
 
#pragma argsused
int main(int argc, char* argv[])
{
int cnt=0, i, m;
char *str="I can use the online Help system from the Help menu.";
for (i=0; i<strlen(str); i++)
 if (str[i]>='a' && str[i]<='z' && str[i]!=' ' && strlen(str)<=4)
  cnt++;
printf("Stroka = %s", str);
printf("\nDlina slov = %d", cnt);
getchar();
}
//---------------------------------------------------------------------------