цель задачи - собрать из двух в од
ин калькулятор который переводит из 16 в 10ричную систему счисления..помогите, а?
код перевода:
| C++ |
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| #include <iostream.h>
#include <conio.h> // for clrscr() & getche() functions...
#include <stdlib.h> // for exit() function...
const int ESC = 27; // Used for escape sequince
int main()
{
int key = 0;
int choise = 0;
long number;
while(key != ESC)
{
cout << "Choose Your Number Base\n";
cout << "\n\t1. Hexadecimal.";
cout << "\n\t2. Octal.";
cout << "\n\t3. Decimal.";
cout << "\n\t4. Exit.\n\t ";
cin >> choise;
switch(choise)
{
case 1: clrscr();
cout << "Enter a Hex number: ";
cin >> hex >> number;
cout << "\n value in octal = "
<< oct << number << endl;
cout << " value in decimal = "
<< dec << number << endl;
break;
case 2: clrscr();
cout << "Enter a Octal number: ";
cin >> oct >> number;
cout << "\n value in hex = "
<< hex << number << endl;
cout << " value in decimal = "
<< dec << number << endl;
break;
case 3: clrscr();
cout << "Enter a dec number: ";
cin >> dec >> number;
cout << "\n value in octal = "
<< oct << number << endl;
cout << " value in hex = "
<< hex << number << endl;
break;
case 4: clrscr();
cout << "Program terminated by user...";
exit(0);
break; //Unreachable code....
default : clrscr();
cout << "ERROR ~ Invalid selection\n\n";
break;
}
cout << "Press any key to continue or 'Esc' to exit";
key = getche();
clrscr();
}
cout << "Program terminated by user...";
return 0;
} |
|
и код элементарного калькулятора:
| C++ |
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| #include <cstdlib>
#include <iostream>
using namespace std;
int main()
{
double num;
double num2;
char choice;
for (;;){
do {
cout<<"Dobro pojalovat' v calc\n";
cout<<"vyberite opciu, kotoraya vam neobhodima. dlya vyhoda najmite 'q'\n";
cout<<"1 - Slojenie\n";
cout<<"2 - Vy4itanie\n";
cout<<"3 - Delenie\n";
cout<<"4 - Umnojenie\n";
cin>>choice;
} while ( choice < '1' || choice > '4' && choice != 'q');
if (choice == 'q') break;
switch (choice) {
case '1':
cout<<"vvodite 1 slagaemoe\n";
cin>>num;
cout<<"vvodite 2 slagaemoe\n";
cin>>num2;
cout<<num + num2;
cout<<"\n";
break;
case '2':
cout<<"vvodite 1 vy4itaemoe\n";
cin>>num;
cout<<"vvodite 2 vy4itaemoe\n";
cin>>num2;
cout<<num - num2;
cout<<"\n";
break;
case '3':
cout<<"vvodite delimoe\n";
cin>>num;
cout<<"vvodite delitel'\n";
cin>>num2;
cout<<num / num2;
cout<<"\n";
break;
case '4':
cout<<"vvodite 1 umnojaemoe\n";
cin>>num;
cout<<"vvodite 2 umnojaemoe\n";
cin>>num2;
cout<<num * num2;
cout<<"\n";
break;
}
}
return 0;
} |
|
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