Взлом банка через SQL

SELECT DISTINCT v.fname, v.lname, i.year, i.location, i.report_file
FROM   Incident AS i
       LEFT JOIN V(ictim?)...  -- presumably v.incident_id = i.id
       LEFT JOIN Keyword AS k ON k.incident_id = i.id
WHERE  i.year BETWEEN 1947 AND 1966
AND    i.type = 'HOMICIDE'
AND    v.sex = 'F'
AND    i.status = 'UNSOLVED'
AND    ...
       OR v.fname IN ('Mari', 'Magda')
       OR SUBSTR ...
AND    (k.keyword IN ('rape', 'decapitation', 'dismemberment', 'fire', 'altar', 'priest', 'prostitute')
       ...
       AND SUBSTR(v.fname, 1, 1) = 'R' AND SUBSTR(v.lname, 1, 1) = 'L');
 
+--------+---------+------+-----------+----------------------------------+
| fname  | lname   | YEAR | location  | report_file                      |
+--------+---------+------+-----------+----------------------------------+
| Anna   | Wedin   | 1956 | Mark      | FULL POLICE REPORT NOT DIGITIZED |
| Linda  | Janson  | 1955 | Mariestad | FULL POLICE REPORT NOT DIGITIZED |
| Simone | Grau    | 1958 | Goteborg  | FULL POLICE REPORT NOT DIGITIZED |
| Lea    | Persson | 1962 | Uddevalla | FULL POLICE REPORT NOT DIGITIZED |
| Kajsa  | Severin | 1962 | Dals-Ed   | FULL POLICE REPORT NOT DIGITIZED |
+--------+---------+------+-----------+----------------------------------+

mysql> SELECT COUNT(*) FROM Users;
+----------+
| COUNT(*) |
+----------+
|  2561078 |
+----------+
1 ROW IN SET (0.83 sec)

mysql> SELECT COUNT(*) FROM Users WHERE SUBSTR( ID , 1, 1) = '1';
+----------+
| COUNT(*) |
+----------+
|  2363285 |
+----------+
1 ROW IN SET (8.73 sec)
 
mysql> SELECT COUNT(*) FROM Users WHERE ID LIKE '1%';
+----------+
| COUNT(*) |
+----------+
|  2363285 |
+----------+
1 ROW IN SET (1.37 sec)