Делаю проект - интернет-магазин. Соотвественно, нужна аутентификация. Все настроила, но все равно одна и та же ошибка. Гугл не помогает
Загнала в базу админа
admin@gmail.com и пароль 03ac674216f3e15c761ee1a5e255f067953623c8b388b4459e13f978d7c846f4
(зашифрованный "1234")
После того, как ввожу эти данные мне кидает ошибки
Прикрепляю инфо
web.xml
| XML |
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
| <?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<welcome-file-list>
<welcome-file>faces/index.xhtml</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.jsf</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.faces</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.xhtml</welcome-file>
</welcome-file-list>
<login-config>
<auth-method>FORM</auth-method>
<realm-name>jdbcRealm</realm-name>
<form-login-config>
<form-login-page>/login.xhtml</form-login-page>
<form-error-page>/login.xhtml</form-error-page>
</form-login-config>
</login-config>
<security-constraint>
<web-resource-collection>
<web-resource-name>Защищённые страницы</web-resource-name>
<description/>
<url-pattern>/admin/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>ADMINS</role-name>
</auth-constraint>
</security-constraint>
</web-app> |
|
glassfish-web.xml
| XML |
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
| <?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE glassfish-web-app PUBLIC "-//GlassFish.org//DTD GlassFish Application Server 3.1 Servlet 3.0//EN" "http://glassfish.org/dtds/glassfish-web-app_3_0-1.dtd">
<glassfish-web-app error-url="">
<!--<context-root>/</context-root>-->
<security-role-mapping>
<role-name>USERS</role-name>
<group-name>USERS</group-name>
</security-role-mapping>
<security-role-mapping>
<role-name>ADMINS</role-name>
<group-name>ADMINS</group-name>
</security-role-mapping>
<class-loader delegate="true"/>
<jsp-config>
<property name="keepgenerated" value="true">
<description>Сохранение копии сгенерированного java кода для класса сервлета.</description>
</property>
</jsp-config>
</glassfish-web-app> |
|
И вот метод из UserController
| Java |
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
| public String login() {
FacesContext context = FacesContext.getCurrentInstance();
HttpServletRequest request = (HttpServletRequest) context.getExternalContext().getRequest();
String result;
try {
request.login(this.getUsername(), this.getPassword());
this.user = ejbFacade.getUserByEmail(getUsername());
this.getAuthenticatedUser();
if (isAdmin()) {
result = "/admin/index";
} else {
result = "/index";
}
} catch (ServletException ex) {
Logger.getLogger(UserController.class.getName()).log(Level.SEVERE, null, ex);
result = "login";
}
return result;
} |
|
Как исправить ошибку?
(
