Даны два массива. Найти среднее арифметическое элементов каждого и сравнить эти значения - C++ - Ответ 5481724

#include <iostream>
#include <random>
 
template <class Iterator>
double arrayAverage(Iterator beginIterator, Iterator lastIterator, size_t vectorSize)
{
    double vectorsElementsSum(0);
    while (beginIterator != lastIterator) {
        vectorsElementsSum += *beginIterator;
        ++beginIterator;
    }
    return ((double)(vectorsElementsSum) / (double)vectorSize);
}
 
int main()
{
    std::default_random_engine generator;
    std::uniform_int_distribution <> distribution(5, 10);
 
    size_t firstArraySize;
    std::cout << "Size of the first array: ";
    std::cin >> firstArraySize;
 
    double firstArrayAverage;
    int *firstArray = new int[firstArraySize];
    std::cout << "First array: " << std::endl;
    for (size_t i = 0; i < firstArraySize; i++)
        std::cout << (firstArray[i] = distribution(generator)) << ' ';
    std::cout << std::endl << "Average: " << (firstArrayAverage = arrayAverage(firstArray, firstArray + firstArraySize, firstArraySize)) << std::endl;
    delete [] firstArray;
 
    size_t secondArraySize;
    std::cout << std::endl << "Size of the second array: ";
    std::cin >> secondArraySize;
 
    double secondArrayAverage;
    int *secondArray = new int[secondArraySize];
    std::cout << "First array: " << std::endl;
    for (size_t i = 0; i < secondArraySize; i++)
        std::cout << (secondArray[i] = distribution(generator)) << ' ';
    std::cout << std::endl << "Average: " << (secondArrayAverage = arrayAverage(secondArray, secondArray + secondArraySize, secondArraySize)) << std::endl;
    delete [] secondArray;
 
    std::cout << ((firstArrayAverage > secondArrayAverage) ? "First average bigger than second" : "Second average bigger than first") << std::endl;
 
    std::system("pause");
    return 0;
}