Работа рекурсии Python3

Matrix: 
[1,2]
[3,4]

Matrix:
[4]

def createMatrix():
    global size
    a = []
    for t in range(size):
        a.append([])
        for k in range(size):
            a[t].append(0)
    print("Введите элементы матрицы")
    for t in range(size):
        for k in range(size):
            a[t][k] = int(input())
 
    return a
 
 
def printMatrix(Matrix):
    for a in Matrix:
        print(a)
 
 
def newMatrix(Matrix,j):
    print("old matrix:")
    printMatrix(Matrix)
    del Matrix[0]
    for t in range(len(Matrix)):
        for k in range(len(Matrix[t])):
            if k == j:
                del Matrix[t][k]
    print("new matrix:")
    printMatrix(Matrix)
    return Matrix
 
 
def determinant(Matrix):
    print("Matrix to determinate:")
    printMatrix(Matrix)
    print('size = ',len(Matrix),' x ',len(Matrix[0]))
    if (len(Matrix) == 1 and len(Matrix[0]) == 1):
        print("True")
        print("Matrix[0][0] = ", Matrix[0][0])
        return Matrix[0][0]
    else:
        det = 0
        for j in range(len(Matrix)):
            print("j = ",j)
            print("Matrix: ")
            printMatrix(Matrix)
            det += ((-1)**(1+j+1))*Matrix[0][j]*determinant(newMatrix(Matrix,j))
            print("det = ",det)
        return det
 
size = int(input("Введите размер матрицы \n"))
a = createMatrix()
D = determinant(a)

Введите размер матрицы 
2
Введите элементы матрицы
1
2
3
4
Matrix to determinate:
[1, 2]
[3, 4]
size =  2  x  2
j =  0
Matrix: 
[1, 2]
[3, 4]
old matrix:
[1, 2]
[3, 4]
new matrix:
[4]
Matrix to determinate:
[4]
size =  1  x  1
True
Matrix[0][0] =  4
det =  4
j =  1
Matrix: 
[4]
Traceback (most recent call last):
  File "tests.py", line 54, in <module>
    D = determinant(a)
  File "tests.py", line 48, in determinant
    det += ((-1)**(1+j+1))*Matrix[0][j]*determinant(newMatrix(Matrix,j))
IndexError: list index out of range