Вывести данные в одну строку

SELECT ConsultantKey,
        CASE WHEN [201303] >  12000 THEN [201303] ELSE 0 END,
        CASE WHEN [201304] >  12000 THEN [201304] ELSE 0 END,
        CASE WHEN [201305] >  12000 THEN [201305] ELSE 0 END,
        CASE WHEN [201306] >  12000 THEN [201306] ELSE 0 END,
        CASE WHEN [201307] >  12000 THEN [201307] ELSE 0 END,
        CASE WHEN [201308] >  12000 THEN [201308] ELSE 0 END,
        CASE WHEN [201309] >  12000 THEN [201309] ELSE 0 END
    FROM ConsultantProduction PIVOT (SUM(WholeSale) FOR ProductionMonthKey IN ([201303], [201304], [201305], [201306], [201307], [201308], [201309])) T

DECLARE @keys AS NVARCHAR(MAX), @sales AS NVARCHAR(MAX), @key AS BIGINT, @sale AS DECIMAL(19, 2)
SET @keys = 'consultantkey '
DECLARE mycursor CURSOR FOR 
SELECT ProductionMonthKey, WholeSale FROM ConsultantProduction
OPEN mycursor
FETCH NEXT FROM mycursor INTO @key, @sale
WHILE @@FETCH_STATUS = 0
BEGIN
     IF (@sale > 12000) SET @keys += CONVERT(nvarchar(6), @key) + ' '
     ELSE SET @keys += CONVERT(nvarchar(6), @key) + ' ' + '0' + ' '
     FETCH NEXT FROM mycursor INTO @key, @sale
END 
CLOSE mycursor;
DEALLOCATE mycursor;
SELECT @keys

select d.ConsultantKey, stuff(
  (select ','+case when c.WholeSale<12000 then '0' else c.ProductionMonthKey end
    from ConsultantProduction c
    where c.ConsultantKey=d.ConsultantKey
    order by c.ProductionMonthKey
    for xml path('')
    ),
  1,1,'')lst
from (select distinct ConsultantKey from ConsultantProduction) d

select d.ConsultantKey, stuff(
  (select case when c.WholeSale < 12000 then '0' else c.ProductionMonthKey end
    from ConsultantProduction c
    where c.ConsultantKey = d.ConsultantKey
    order by c.ProductionMonthKey
    for xml path('')
    ),
  1,1,'')lst
from (select distinct ConsultantKey from ConsultantProduction) d