Простой конвертер, реализация

mydict={
    'mile':'1609 m',
    'yard':'0.9144 m',
    'foot':'30.48 cm',
    'inch':'2.54 m',
    'km':'1000 m',
    'm':'1 m',
    'cm':'0.01 m',
    'mm':'0.001 m',
}
 
def converter(arr):
    val=0
    v1=mydict[arr[1]].split(" ")
    v2=mydict[arr[3]].split(" ")
    if v1[1]!="m":
        v2=mydict[v1[1]]
        val=float(v2.split(" ")[0])
        val=val*float(v1[0])
    else:
        val=float(v1[0])/float(v2[0])
 
    val=val*float(arr[0])
    print('Результат равен '+str(val)+' '+arr[3])
    return 0
 
 
test=["5.3 km in cm","22.39 foot in m","10200 mm in yard","15.5 mile in km"]
 
for i in range(len(test)):
    converter(test[i].split(" "))

def distance_converter(from_,from_number,to):
    '''
    Distance converter function
    
    Example: 5 yard to foot
    
    arg from_ -- from what distance type?
        e.g 'yard' (type must be str)
    
    arg from_number -- distance number
        e.g 5 (type must be int | float)
    
    arg to -- to what system type?
        e.g 'foot' (type must be str)
    '''
    dis_dict = {
        'mile': (0.000621371,1609.34, '/'),
        'yard': (0.9144, 1.09361, '*'),
        'foot': (0.3048, 3.28084, '*'),
        'inch': (0.02, 39.3701, '*'),
        'km'  : (1000, 1, '/'),
        'm'   : (1, 1, '*'),
        'cm'  : (0.01,100,'*'),
        'mm'  : (0.001,1000,'*')
    }
    to_meters = dis_dict[from_.lower()][0] * from_number
    if dis_dict[to][2] == '*':
        to_distance = to_meters * dis_dict[to.lower()][1]
    else:
        to_distance = to_meters / dis_dict[to.lower()][1]
      
    return to_distance 
 
 
print(distance_converter('yard',5,'foot'))

str.split()