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Another LITTLE test of mine to see if my little change WOULD actually work. I have no idea IF it will. But hey, worth a try! #исходная строка
(Another [LITTLE] test of mine to see if my little change [WOULD] actually work). I have no idea [IF] it will. But hey, worth a try!

s="Another LITTLE test of mine to see if my little change WOULD actually work. I have no idea IF it will. But hey, worth a try!"
rus1="абвгдеёжзийклмнопрстуфхцчшщъыьэюя"
rus2="АБВГДЕЁЖЗИЙКЛМНОПРСТУФХЦЧШЩЪЫЬЭЮЯ"
ukr1="абвгґдеєжзиіїйклмнопрстуфхцчшщьюя"
ukr2="АБВГҐДЕЄЖЗИІЇЙКЛМНОПРСТУФХЦЧШЩЬЮЯ"
eng1="abcdefghijklmnopqrstuvwxyz"
eng2="ABCDEFGHIJKLMNOPQRSTUVWXYZ"
space=" "
letters=rus1+rus2+ukr1+ukr2+eng1+eng2+space
cap=rus2+ukr2+eng2
vow=["а", "е", "ё", "і", "и", "й", "о", "у", "ы", "э", "я", "ю", "є", "ї", "a", "e", "i", "y", "o", "u"]
sen=[".", "!", "?"]
 
#1 задание
flag = 0
k = 0 
print("1) Print words that consist of capital letters:")
for c in s:
 
    if c in cap and flag == 0:
        w = c
        flag = 1
        continue
 
    if c in cap and flag == 1:
        w =  w + c 
        continue    
 
    if c not in cap and flag == 0:
        continue 
 
    if c not in cap and flag == 1:
        flag = 0
        wlen=len(w)
        if wlen>1:
            print(w)
#3 задание
            print('[',w,']')
 
#2 задание
sentence=0
flag=0
mem1=0
mem2=0
lesen=0
s=s.lower()
for c in s:
    if c in letters and flag==0:
        w=c
        flag=1
        if c!=vow:
                mem1+=1
                continue
        continue
    if c in letters and flag==1:
        w=w+c
        if c!=vow:
                mem1+=1
                continue
        continue
    if c in sen and flag==1:
        flag=0
        sentence+=1
        if mem1>mem2:
                mem2=mem1
                lesen=sentence
                mem1=0
 
print("2) Sentence with most consonants is", lesen)

s="Another LITTLE test of mine to see if my little change WOULD actually work. I have no idea IF it will. But hey, worth a try!"
 
# 1
print(re.findall(r'[A-Z]+', s))
 
# 3
print(re.sub(r'\b([A-Z]+)\b', r'[\1]', s))