Самая частая буква

a = input()
ans = 0
g=''
l=''
k=''
for i in range(len(a)):
    c = a[i]
    c = a[i].lower()
    if ord(c) != 32:
        g += c
for i in g:
    b = g.count(i)
    if b>ans:
        l = i
        ans = b
print(l.upper())
print(ans)

from collections import Counter
 
 
word = ''.join([i.upper() for i in input() if i.isalpha()])
mx = max(Counter(word).values())
print(''.join(sorted(set([i for i in word if word.count(i) >= mx]))), mx, sep='\n')

s = input()
a=[]
m = 0
s = s.upper()
end = []
alphabet = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
for i in range(0,26):
    a.append(s.count(alphabet[i]))
m = max(a)
idx = [i for i,x in enumerate(a) if x == m]
for i in range(len(idx)):
    end.append(alphabet[idx[i]])
    result = ''.join(end)
print(result)
print(m)

def counter(input_string=None):
    """Count the occurrences of each character in a string. Exclude spaces and punctuation. returns all max word count and the word with the max count"""
    if input_string is None:
        input_string = input("Enter a string: ")
    char_count = {}
    for char in input_string:
        if char.isalnum():  # Exclude spaces and punctuation
            char = char.capitalize()
            if char in char_count:
                char_count[char] += 1
            else:
                char_count[char] = 1
    print("Character count:", char_count)
    if char_count:
        max_count = max(char_count.values())
        max_chars = [char for char, count in char_count.items() if count == max_count]
        print(f"Characters: {' '.join(max_chars)} \r\n Max character count: {max_count} ")
    else:
        print("No valid characters found.")
 
 
 
if __name__ == "__main__":
    counter("- We all live in the Yellow Submarine!")