3 подряд стоящих символа

rus = 'йцукенгшщзхъфывапролджэячсмитьбю'
eng = "qwertyuiop[]asdfghjkl;'zxcvbnm,."
 
 
def _pair(index: int) -> tuple:
    return rus[index], eng[index]
 
 
def is_three_sequence(value: str) -> bool:
    A_LEN = 32  # длина алфавита (без ё)
    word = value.lower()
    if len(word) < 3:
        return False
    for i in range(0, len(word) - 2):
        if word[i] not in rus and word[i] not in eng:
            continue
        ind = word[i] in rus and rus.index(word[i]) or eng.index(word[i])
        if ind + 1 < A_LEN and word[i + 1] in _pair(ind + 1) and ind + 2 < A_LEN and word[i + 2] in _pair(ind + 2):
            print(word[i:i + 3])  # это можно убрать, для отладки
            return True
    return False
 
 
if __name__ == '__main__':
    assert is_three_sequence('qwe') is True
    assert is_three_sequence('вмнкрапр') is True
    assert is_three_sequence('фыqцуд') is True
    assert is_three_sequence('фыded') is True
    assert is_three_sequence('aь,ю') is True
    assert is_three_sequence('FGр') is True
    assert is_three_sequence('qaz') is False
    assert is_three_sequence('qer') is False
    assert is_three_sequence('ыар') is False
    assert is_three_sequence('cvx') is False
    assert is_three_sequence('бю.') is False