Задача Найти Еду

data = ['2 15 148 3 6 12 9', '23 32 1 2 22 122 1', '3 12 85 7', '1984 42 13 7 5']
print(*find_food(*data), sep="\n")

data = ['1 2 15 14 8 3 6 12 9', '2 3 3 2 1 2 5 2 1 7 2 4', '3 12 8 5 7', '19 8 4 42 13 7 5']
print(*find_food(*data, regularize=False, reduce=2), sep="\n")

def find_food(*args, **kwargs):
    sred = {}
    count = {}
    min_sr = {}
    for i in range(len(args)):
        it = args[i].split()
        items = []
        sumi = 0
        count[i] = len(it)
        for item in it:
            sumi += int(item)
            items.append(int(item))
        sred[i] = sumi / len(it)
        items2 = []
        for itf in items:
            if itf > sred[i]:
                items2.append(itf)
        min_sr[i] = min(items2)
 
    na_vyvod = []
    for item in min_sr:
        if 'reduce' in kwargs:
            na_vyvod.append((count[item], min_sr[item] // kwargs['reduce']))
        else:
            na_vyvod.append((count[item], min_sr[item]))
 
    if 'regularize' in kwargs:
        reversed = not kwargs['regularize']
        na_vyvod = sorted(na_vyvod, reverse=reversed)
    return na_vyvod

data = ['2 15 148 3 6 12 9', '23 32 1 2 22 122 1', '3 12 85 7', '1984 42 13 7 5']
 
def find_food(d):
    n = list(map(lambda x: x.split(), d))
    for i in range(len(n)):
        n[i] = list(map(int, n[i]))
        m = sum(n[i]) / len(n[i])
        n[i] = tuple([len(n[i]), min(list(filter(lambda x: x > m, n[i])))])
    return n
 
print(*find_food(data), sep="\n")