ValueError: invalid literal for int() with base 10

import requests
from bs4 import BeautifulSoup
 
URL = 'http://shop.k-dr76.ru/catalog/zapchasti-chery/amulet/detali_dvigatelya/'
HEADERS = {'user-agent': 'Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:86.0) Gecko/20100101 Firefox/86.0',
           'accept': '*/*'}
HOST = 'http://shop.k-dr76.ru'
 
 
def get_html(url, params=None):
    r = requests.get(url, headers=HEADERS, params=params)
    return r
 
def get_pages_count(html):
    soup = BeautifulSoup(html, 'html.parser')
    pagination = soup.find_all(class_='pages')
    if pagination:
        return int(pagination[-1].get_text())
    else:
        return 1
 
 
def get_content(html):
    soup = BeautifulSoup(html, 'html.parser')
    items = soup.find_all('div', class_='prod fix')
 
    parts = []
    for item in items:
        parts.append({
         'title': item.find('div', class_='name').get_text(strip=True),
         'cuntry': item.find('span', class_='prop-name').get_text(strip=True),
         'articl': item.find('span', class_='prop-value').get_text(strip=True),
         })
    return parts
 
 
def parse():
    html = get_html(URL)
    if html.status_code == 200:
        parts = []
        pages_count = get_pages_count(html.text)
        for page in range(1, pages_count + 1):
            print(f'Парсинг страницы {page} из {pages_count} ...')
            html = get_html(URL, params={'page': page})
            parts.extend(get_content(html.text))
        print(parts)
    else:
        print(error)
 
 
parse()

pagination = soup.find_all('a', class_="pagination__item")

C:\Users\makgeer\PycharmProjects\untitled\venv\Scripts\python.exe C:/Users/makgeer/Downloads/wwwparpython1/test.py
Traceback (most recent call last):
  File "C:/Users/makgeer/Downloads/wwwparpython1/test.py", line 51, in <module>
    parse()
  File "C:/Users/makgeer/Downloads/wwwparpython1/test.py", line 41, in parse
    pages_count = get_pages_count(html.text)
  File "C:/Users/makgeer/Downloads/wwwparpython1/test.py", line 18, in get_pages_count
    return int(pagination[-1].get_text())
ValueError: invalid literal for int() with base 10: '1\n2\n3\n4\n5'
 
Process finished with exit code 1