Заполнить массив по правилу, где половина массива заполняется случайными числами в диапазоне между а и b

import random
 
def main():
    N = 10
    a, b = sorted(map(int, input().split(maxsplit = 2)))
    l = [random.randrange(a, b) for n in range(N // 2)]
    squares = [n * n for n in l]
    print(l + squares)
    
if __name__ == "__main__":
    main()

from random import randint
 
a, b = sorted(int(i) for i in input().split())
 
lst = []
for i in range(10):
    lst.append(randint(a, b) if i < 5 else lst[i - 5] ** 2)
 
print(lst)

a=int(input())
b=int(input())
from random import randint
A = [0]*10
for i in range(0,5):
    A[i] = [ randint(a,b) ]
for i in range(6,10):
    A[i]=A[i]*A[i]
    
print(A)

a=int(input())
b=int(input())
from random import randint
A = [0]*10
for i in range(0,5):
  A[i] = randint(a,b)
print(A)
 
i = 0
for j in range(5,10):
  A[j]=A[i]*A[i]
  i += 1
 
print(A)

A[i]=A[i - 5]*A[i - 5]

from random import randint
 
a, b = sorted(map(int, input().split()))
lst = [randint(a, b) for _ in range(5)]
print(lst + list(map(lambda x: x * x, lst)))

from random import randint
a, b = map(int, input().split()) 
if a > b:
    a, b = b, a
A = [randint(a, b) for i in range(10)]
for i in range(5, 10):
    A[i] = A[i-5]*A[i-5]
print(*A)