Используя срезы извлечь нечетные элементы матрицы

A = array([[n+m*10 for n in range(5)] for m in range(5)])

A[::2]

for i in array[1::2]:
    print(i[1::2])

A = array([[n+m*10 for n in range(5)] for m in range(5)])
 
for i in array[1::2]:
    print(i[1::2])

A = [[n+m*10 for n in range(5)] for m in range(5)]
for x in A[1::2]:
    print(x[1::2])

arr = array([[n+m*10 for n in range(5)] for m in range(5)])
print(arr)
 
for i in arr[1::2]:
    print(i[1::2])

def get_odd_elem( matr ):
    m = len( matr[0] )
    new_matr = []
    for i in range( len(matr) ):
        new_matr.append( matr[i][0 if not (m % 2) else i % 2: m: 2] )
    return new_matr
#==============================================================================
def print_matr( matr ):
    print(*matr, sep='\n')
    print()
#==============================================================================
A = [
    [1,2,3,4,5],
    [6,7,8,9,10],
    [11,12,13,14,15]
]
B = [
    [1,2,3,4],
    [5,6,7,8],
    [9,10,11,12]
]
print_matr(A)
print_matr( get_odd_elem(A) )
print_matr(B)
print_matr( get_odd_elem(B) )

arr = [[n+m*10 for n in range(5)] for m in range(5)]
print(arr)
 
for i, v in enumerate(arr):
    print(v[(i+1)%2::2])
 
##################
import numpy as np
arr = np.arange(1,25)
res = arr[arr%3==0]
print(res)