Синтакс эрор. Подскажите пожалуйста где синтаксическая ошибка в 54 строке?

import math
K1, M, K2, P2, N2 = map(int, input().split())
if (K1 <= 0 or M <= 0 or K2 <= 0 or P2 <= 0 or N2 <= 0) or (M < N2):
print(-1, -1)
else:
if N2<M:
a = ((P2-1)*M) + N2
if K2 % a == 0:
b = (K2//a)
else:
b = ((K2//a)+1)
if K1 % (M * b) == 0:
pod = (K1 // (M * b))
else:
pod = (K1 // (M * b) + 1)
if N2 == M:
a = (P2*M)
if K2 % a == 0:
b = (K2//a)
else:
b=((K2//a)+1)
if K1 % (M * b) == 0:
pod = (K1 // (M * b))
else:
pod = (K1 // (M * b) + 1)
etaj = math.ceil((K1 - (pod - 1) * b * M) / b)
if etaj > M:
while etaj > M:
etaj -= M
pod += 1
if K2 < P2 * N2 or N2 > M or K2 // P2 < M or K2 < P2 * M:
pod = -1
etaj = -1
if M == 1:
pod = 0
elif (P2 == 1 and N2 == 1 and M * K2 >= K1):
pod = 1
etaj = 0
elif P2==1 and K2>=K1 and N2==1:
pod = 1
etaj = 1
elif P2==1 and K2<K1 and N2==1 and K1 < K2 * M:
pod = 1
etaj = 0
elif P2==1 and K2<K1 and N2==1 and K1 > K2 * M:
pod = 0
etaj = 0
if N2 != 1 and P2 != 0:
ma = ((K2 - 1) // ((N2 - 1) + (P2 - 1) * M))
mi = b
else:
ma = -2
mi = -2
elif ((K2 // (M * b)) + 1 != P2 and P2 != 1):
pod = -1
etaj = -1
elif (b < mi and mi != -2) or (b > ma and ma != -2):
pod = -1
etaj = -1
elif mi != ma and mi != -2 and ma != -2:
etaj = 0
print(pod, etaj)Добавлено через 35 секунд
import math
K1, M, K2, P2, N2 = map(int, input().split())
if (K1 <= 0 or M <= 0 or K2 <= 0 or P2 <= 0 or N2 <= 0) or (M < N2):
print(-1, -1)
else:
if N2<M:
a = ((P2-1)*M) + N2
if K2 % a == 0:
b = (K2//a)
else:
b = ((K2//a)+1)
if K1 % (M * b) == 0:
pod = (K1 // (M * b))
else:
pod = (K1 // (M * b) + 1)
if N2 == M:
a = (P2*M)
if K2 % a == 0:
b = (K2//a)
else:
b=((K2//a)+1)
if K1 % (M * b) == 0:
pod = (K1 // (M * b))
else:
pod = (K1 // (M * b) + 1)
etaj = math.ceil((K1 - (pod - 1) * b * M) / b)
if etaj > M:
while etaj > M:
etaj -= M
pod += 1
if K2 < P2 * N2 or N2 > M or K2 // P2 < M or K2 < P2 * M:
pod = -1
etaj = -1
if M == 1:
pod = 0
elif (P2 == 1 and N2 == 1 and M * K2 >= K1):
pod = 1
etaj = 0
elif P2==1 and K2>=K1 and N2==1:
pod = 1
etaj = 1
elif P2==1 and K2<K1 and N2==1 and K1 < K2 * M:
pod = 1
etaj = 0
elif P2==1 and K2<K1 and N2==1 and K1 > K2 * M:
pod = 0
etaj = 0
if N2 != 1 and P2 != 0:
ma = ((K2 - 1) // ((N2 - 1) + (P2 - 1) * M))
mi = b
else:
ma = -2
mi = -2
elif ((K2 // (M * b)) + 1 != P2 and P2 != 1):
pod = -1
etaj = -1
elif (b < mi and mi != -2) or (b > ma and ma != -2):
pod = -1
etaj = -1
elif mi != ma and mi != -2 and ma != -2:
etaj = 0
print(pod, etaj)

0

Сообщение от Jonatan Jostar где синтаксическая ошибка в 54 строке?

В 54 строке вестимо

Добавлено через 20 секунд
elif после else

0

Код вот сюда надо поместить

2