Написать функцию, которая прочитает заданный файл

f_out.write(re.sub(r'(?ms)<.+?>', '', f_in.read()))

from bs4 import BeautifulSoup
import requests
 
with open("D:\загрузки\draft (4).html", 'w'):
    src = file.read("D:\загрузки\draft (4).html")
print(src)

from bs4 import BeautifulSoup
import requests
 
def parse():
    URL = 'file:///D:/%D0%B7%D0%B0%D0%B3%D1%80%D1%83%D0%B7%D0%BA%D0%B8/draft%20(4).html'
    HEADERS = {
        'User-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/104.0.0.0 Safari/537.36'
    }
 
    reasponse = requests.get(URL, headers = HEADERS)
    soup = BeautifulSoup(response.content, 'html.parser')
    items = soup.findAll('div', class_ = 'container')
    comps = []
 
    for item in items:
        comps.append({
            'title': item.find('div', class_ = 'col-lg').get_text(strip = True)
        })
        for comp in comps:
            print(comp['title'])
 
parse()

import re
 
 
def foo(fi, fo):
    with open(fi, 'r', encoding='utf-8') as f_in, open(fo, 'w', encoding='utf-8') as f_out:
        f_out.write(re.sub(r'(?ms)<.+?>', '', f_in.read()))
 
 
foo('draft.html', 'result.txt')