Олимпиадная задача на подбор

a = ['20', '52', '65']
x = int(a[0])
y = int(a[1])
z = int(a[2])
tra = 0
trb = 0
trc = 0
r1 = 0
r2 = 0
def checker(x, y, z):
    if len(x) and len(y) and len(z) == 2:
        r1 = 1
        r2 = 100
        return r1,r2
    elif len(x) and len(y) and len(z) == 3:
        r1 = 10
        r2 = 1000
        return r1,r2
    elif len(x) and len(y) and len(z) == 4:
        r1 = 100
        r2 = 10000
        return r1,r2
    else:
        r1 = 1000
        r2 = 100000
        return r1,r2
rng = checker(a[0], a[1], a[2])
rr1 = rng[0]
rr2 = rng[1]
for c in range(rr1, rr2):
    for b in range(rr1, rr2):
        for a in range(rr1, rr2):
            if x != a * b and y != b * c and z != a * c:
                pass
            elif x ==  a *b and y == b *c and z == a *c:
                tra = a
                trb = b
                trc = c
print(tra, trb, trc)

# x, y, z = 20, 52, 65
x, y, z = 4082420, 4086462, 4084440
 
c = (z * y / x)**0.5 
b = y / c
a = z / c
 
if all([a.is_integer(), b.is_integer(), c.is_integer()]):
    print(x, y, z, '>', *map(int, [a,b,c]))

x, y, z = sorted(map(int, input().split()))
 
d = 1
while True:
    if not (x%d | y%d) and x//d*y//d == z:
        print(d, x//d, y//d)
        break
    d += 1

from math import isqrt
 
x, y, z = map(int, input().split())
s = isqrt(x * y * z)
print(s // x, s // y, s // z)