Получить все перестановки цифр трехзначного числа

from random import randint
from itertools import permutations as per
 
 
[print(*i) for i in per(str(randint(100, 1000)))]

def all_perms(n):
    if (n==1):
        return [[1]]
    else:
        tmp=all_perms(n-1)
        res=[]
        for p in tmp:
            for i in range(n):
                res.append(p[0:i]+[n]+p[i:])
        return res
 
while True:
    n=randint(100,999)
    sn=str(n)
    if sn[0] != sn[1] and sn[1] != sn[2] and sn[0] != sn[2]:
        perms=all_perms(3)
        for p in perms:
            tmp=""
            for i in p:
                tmp=tmp+sn[i-1]
            print(int(tmp))  
        break

sn=str(n)
if sn[0] != sn[1] and sn[1] != sn[2] and sn[0] != sn[2]:

if '0' not in sn and len(set(sn)) == 3:

from random import choice
n = [0, 0, 0]
d = {1,2,3,4,5,6,7,8,9}
for i in range(3):
    n[i] = choice(list(d))
    d = d - {n[i]}
for i in n:
    for j in n:
        for k in n:
            if not (i==j or j==k or i==k):
                print(''.join(map(str, [i,j,k])))

from random import choice
n = [0, 0, 0]
d = [1,2,3,4,5,6,7,8,9]
for i in range(3):
    n[i] = choice(d)
    d.remove(n[i])
for i in n:
    for j in n:
        for k in n:
            if not (i==j or j==k or i==k):
                print(''.join(map(str, [i,j,k])))