Найти неповторяющиеся и элементы, которые не имеют повторений в исходном списке

lst = [1, 2, 4, 5, 6, 2, 5, 2]

lst2 = [1, 2, 4, 5, 6]

lst = [1, 2, 4, 5, 6, 2, 5, 2]

lst2 = [1, 4, 6]

import random
def gen_list(size, of, to):
    result = []
    for _ in range(size):
        result.append(random.randint(of, to))
    return result

from random import randint
lst = [randint(1, 10) for _ in range(10)]
lst2 = list(set(lst))
lst3 = [x for x in lst2 if lst.count(x) == 1]
print(*lst)
print(*lst2)
print(*lst3)

>>> lst = [1, 2, 4, 5, 6, 2, 5, 2]
>>> list(set(lst))
[1, 2, 4, 5, 6]

>>> import collections
>>> d = collections.OrderedDict()
>>> for i in lst:
...     d[i] = True
... 
>>> list(d.keys())
[1, 2, 4, 5, 6]

>>> lst = [4, 1, 2, 4, 5, 6, 2, 5, 2]
>>> list(set(lst))
[1, 2, 4, 5, 6]
>>> import collections
>>> d = collections.OrderedDict()
>>> for i in lst:  d[i] = True
... 
>>> list(d.keys())
[4, 1, 2, 5, 6]

>>> c = collections.Counter(lst)
>>> c
Counter({2: 3, 5: 2, 1: 1, 4: 1, 6: 1})
>>> [k for k, v in c.items() if v == 1]
[1, 4, 6]

>>> numpy.random.randint(0, 10, size=5)
array([7, 0, 4, 5, 0])

lst = [7, 4, 1, 2, 4, 5, 6, 2, 5, 2]
 
ret = list(dict.fromkeys(lst))
print('уникальные, присутствуют 1 и более раз', ret, sep='\n')
 
dct = {}
for x in lst: dct[x] = dct.get(x, 0) + 1
ret = [k for k, v in dct.items() if v == 1]
print('уникальные, присутствуют ровно 1 раз', ret, sep='\n')

>>> lst = [7, 4, 1, 2, 4, 5, 6, 2, 5, 2]
>>> list(dict.fromkeys(lst))
[1, 2, 4, 5, 6, 7]