Ошибка error C4996: 'strcpy': This function or variable may be unsafe. Consider using strcpy_s instead

#include <iostream>
#include <cstring>
#include <fstream>
#include<string>
#include<iomanip>
 
using namespace std;
 
struct link
{
    int age;
    char firstname[10];
    char name[10];
 
    link *next;
 
};
 
class linklist
{
private: link *first;
 
public: linklist()
{
            first = NULL;
}
 
        void add(char * firstname, char* name, int _age);
        void dis();
        void input();
        void zapus(char * firstname, char* name, int _age);
};
void linklist::add(char * firstname, char* name, int _age)
{
    link *newlink = new link;
    newlink->age = _age;
    strcpy(newlink->firstname,firstname);
    strcpy(newlink->name, name);
 
    newlink->next = first;
    first = newlink;
    }
void linklist::dis()
{
    link *current = first;
    while (current)
    {
        cout << current->firstname << endl << current->name << endl<<current ->age;
        current = current->next;
 
    }
}
 
void linklist::input()
{
    char name[10];
    char firstname[10];
    int age;
    cout << "Enter firstname->";
    cin >> firstname;
    cout << "Enter name->";
    cin >> name;
        cout << "Enter age->";
    cin >> age;
    add(firstname, name, age);
    zapus(firstname, name, age);
 
 
}
void linklist::zapus(char * firstname, char* name, int age)
{
    ofstream fout;
 
    fout.open("text.txt", ios::app);
    fout << "\tName: " << name << "\t Firstname: " << firstname << endl
        << "\t age: " << age << endl;
    fout.close();
}
 
int main()
{
    linklist l1;
    l1.input();
}