Руганье на getline()

#include <iostream>
#include <cstring>
using namespace std;
 
int main()
{
    int ArSize = 20;
    int answer;
    char name[ArSize];
    cout<<"You are the best? ( 1. Yes, 2. No )\n";
    cin>>answer;
    if (answer = 1)
        cout<<"What's you name?\n";
        cin.getline>>(name, ArSize);
        cout<<name<<", well played it's true! You have a good luck, "<<name<<endl;
}

cin.getline>>(name, ArSize);

cin.getline>>

cin.getline(name, ArSize);

if ( answer = 1 )

cout<<"What's you name?\n";

if (answer = 1) {
 
        cout<<"What's you name?\n";
        cin.getline>>(name, ArSize);
        cout<<name<<", well played it's true! You have a good luck, "<<name<<endl;
 
}

#include <iostream>
#include <cstring>
using namespace std;
 
int main()
{
    int ArSize = 20;
    char answer;
    char name[ArSize];
    cout<<"Hello, what's you name?\n";
    cin.getline(name, ArSize);
    cout<<"Hello, "<<name<<endl;
    for (;;)
        {
    cout<<"You are the best? ( Yes - y, No - n )\n";
    cin>>answer;
    if (answer == 'y' && answer == 'Y')
        cout<<"It's true "<<name<<"! You have a good luck "<<name<<".\n";
    else if (answer == 'n' && answer == 'N')
        cout<<"Are you sure? Help: it's number one!\n";
    else
        cout<<"What?\n";
        }
}