Использование значений a1 для подсчета min/max функции

#include <iostream>
#include <algorithm>
#include <cmath>
using namespace std;
int main() {
    float a1, a2, h, h1, b, b1;
    cout << "Vvedite granici a:\n";
    cout << "Nizhnaya granica a ";
    cin >> a1;
    cout << "Verhnaya granica a ";
    cin >> a2;
    cout << "\nEnter a step:\n";
    cout << "h = ";
    cin >> h;
    cout << "\nZnacheniya a\n";
    do {
        cout << " " << a1 << "\n";
        a1 += h;
    } while (a1 <= a2+0.1);
       cout << "\nEnter step b:";
     cin >> h1;
  
cout << "max(a1-1,(-(5+4*a1)+sqrt(25+48*a1))/4)=" << b << endl;
cout << "min(a1-0.5,(-1+sqrt(1+4*a1*(1-a1)))/2)=" << b1 << endl;
    do{
        cout << " " << b1 << "\n";
        b += h1;
    } while (b <= b1+0.05);   
    system("pause");
    return 0;
}

#include <iostream>
#include <cmath>
 
using namespace std;
 
double  foo1(double arg) { return (-(5 + 4 * arg) + sqrt(25 + 48 * arg)) / 4; }
double  foo2(double arg) { return -1 + sqrt(1 + 4 * arg*(1 - arg)) / 2; }
 
int main() {
    double a1, a2;
    cout << "Vvedite granici a:\n";
    cout << "Nizhnaya granica a ";
    cin >> a1;
    cout << "Verhnaya granica a ";
    cin >> a2;
    double h;
    cout << "\nEnter a step:\n";
    cout << "h = ";
    cin >> h;
    
    if (a1 < 0) return -1;
    double max = foo1(a1);
    double min = foo2(a1);
    for (double arg(a1 + h); arg <= a2; arg += h)
    {
        double f1 = foo1(arg);
        double f2 = foo2(arg);
        if (f1 < min) min = f1;
        if (f2 > max) max = f2;
    }
    cout << "min a1-a2, ((-(5 + 4 * arg) + sqrt(25 + 48 * arg)) / 4) = " << min << endl;
    cout << "max a1-a2, (-1 + sqrt(1 + 4 * arg*(1 - arg)) / 2) = " << max << endl;
    
    system("pause");
    return 0;
}