открытие файла по заданному пути c ShellExecuteA

#include <iostream>
#include <string>
#include <fstream>
#include "windows.h"
#include <shellapi.h>
#include <regex>
#include <dos.h>
using namespace std;
 
int main()
{
    char path[64] = { NULL };
    char choise[10000] = "0";
    cmatch res;
    cout << "Do you want open file for watching or for editing?" << endl;
    cin.getline(choise, 10000);
    regex rx("edit");
    regex rx1("watch");
    if (regex_search(choise, res, rx)) {
        system("cls");
        cout << "Path: ";
        gets_s(path, 64);
        ofstream fout(path);
        if (fout.is_open()) {
            system("cls");
            string text;
            cout << "Write down there, what should be in the file: ";
            getline(cin, text);
            fout << text;
        }
        else
            cout << "unable to open file";
    }
    else if (regex_search(choise, res, rx1)) {
        system("cls");
        cout << "Path:\n";
        cin.getline(path, 64);
        ShellExecuteA(NULL, "open", path, NULL, NULL, SW_SHOWNORMAL);
        cout << "Do you want to see, where is your file located?" << endl;
        cout << "write yes or no: ";
        char answer[64];
        cin.getline(answer, 64);        
        regex rx2("yes");
        regex rx3("no");
        if (regex_search(answer, res, rx2)) {
            cout << "When window will be opened type in name of your file";
            Sleep(3000);
            ShellExecuteA(NULL, "find", "D:\work", NULL, NULL, SW_SHOWNORMAL);
        }
        else if (regex_search(answer, res, rx3)) {
            system("cls");
            system("pause");
        }
    }
}