задача про телефонный справочник

struct book {
char fam[20];
char im[20];
char adress[100];
int phone;} lib[5];
 
int main(int argc, char* argv[])
{
int n;
cout<<"kolichestvo abonentov: ";
cin>>n;
for (int i=1; i<=n; i++)
{cout<<"BBedute umia"<<endl; cin>>lib[i].im;
cout<<"BBedute famiJIuy aboHeHTa"<<endl; cin>>lib[i].fam;
cout<<"BBedute adres bez probeJIoB u zapiatblX"<<endl; cin>>lib[i].adress;
cout<<"BBedute HoMeP TeJIeFoHa"<<endl; cin>>lib[i].phone;
}
for (int i=1; i<=n; i++)
cout<<lib[i].im<<" "<<lib[i].fam<<" "<<lib[i].adress<<" "<<lib[i].phone<<endl;
char* a,*b;
int i,j,k;
int t=1;
cout<<"BBedute umia i famiJIuy aboHeHTa KoToPogo XoTuTe HaiTu"; cin>>a>>b;
for (i=1; i<=n; i++) {
if (strlen(a)==strlen(lib[i].im)) {
for (j=1; j<=strlen(a); j++)
if (a[j]!=lib[i].im[j]) { t=0; break;}}
if (strlen(b)==strlen(lib[i].fam)) {
for (k=1; k<=strlen(b); k++)
if (b[j]!=lib[i].fam[k]) { t=0; break;}}
if (t=1) {cout<<lib[i].phone;}}
if (t=0) cout<<"TaKogo obonenta nety";
getchar(); getchar();
return 0;
}

if (t=1) 
{
cout << lib[i].phone; 
}

if (t=1)..  if (t=0)..