Возможен ли метод с типом Task<typeof(y)>

public Task<typeof(y)> X (Type y)
{
return 1 as y;
}

int x = X(typeof(int));
string z = X(typeof(string));

 private async Task<____> Query(string uri)
        {
            string result;
            HttpWebRequest wrq = (HttpWebRequest)WebRequest.Create(uri);
            wrq.CookieContainer = new CookieContainer();
            using (HttpWebResponse response = (HttpWebResponse)await wrq.GetResponseAsync())
            using (Stream responseStream = response.GetResponseStream())
            using (StreamReader readStream = new StreamReader(responseStream, Encoding.UTF8))
            {
                result = await readStream.ReadToEndAsync();
            }
            return result;
        }
 
        public async Task<List<Serial>> Search(string query)
        {
            return (JsonConvert.DeserializeObject<Dictionary<int, Serial>>(await Query(string.Format("{0}shows/search/?q={1}", BaseUrl, query)))).Values.ToList();
        }
        
        public async Task<File> SearchFile(string query)
        {
            return  (JsonConvert.DeserializeObject<File>(await Query(string.Format("{0}shows/search/file/?q={1}", BaseUrl, query))));
        }

 int i = Method<int>();
string str = Method<string>();

public T Method<T>()
        {
            if(typeof(T).FullName == "System.String")
                return (T)("string" as object);
            if (typeof(T).FullName == "System.Int")
                return (T)(5 as object);
            return default(T);
        }