Загрузить картинку и сохранить в базу

openFileDialog1.ShowDialog();
                        pictureBox1.ImageLocation = openFileDialog1.FileName;
                        this.Text = openFileDialog1.FileName;

//получаем байты:
System.IO.FileStream fs = new System.IO.FileStream(openFileDialog1.FileName, System.IO.FileMode.Open, System.IO.FileAccess.Read);
var reclameContent = new byte[fs.Length];
fs.Read(reclameContent, 0, Convert.ToInt32(fs.Length));
fs.Close();
 
//сохраняем (здесь сохраняется хранимкой)
SqlCommand comm = myconnection.CreateCommand();
comm.CommandType = CommandType.StoredProcedure;
comm.CommandText = "add_reclame_campaign";           
comm.Parameters.AddWithValue("rcam_content", reclameContent);
comm.ExecuteNonQuery();

openFileDialog1.ShowDialog();
                        pictureBox1.ImageLocation = openFileDialog1.FileName;
                        this.Text = openFileDialog1.FileName;
System.Drawing.Image img = System.Drawing.Image.FromFile(Text);
System.IO.MemoryStream ms = new System.IO.MemoryStream();
img.Save(ms, System.Drawing.Imaging.ImageFormat.Bmp);
string query = "Insert into TableScheme values(Scheme =@Scheme)";
SqlConnection conn ... 
SqlCommand comm = new SqlCommand(query, conn);
comm.Parameters.Add("@Scheme", SqlDbType.Image).Value = ms.ToArray();
conn.Open();
comm.ExecuteNonQuery();

ConnectionClass connection = new ConnectionClass();
DataTable data_table = connection.queryMethod("INSERT INTO USER VALUES((Scheme =@Scheme))");

openFileDialog1.ShowDialog();
                        pictureBox1.ImageLocation = openFileDialog1.FileName;
                        this.Text = openFileDialog1.FileName;
System.Drawing.Image img = System.Drawing.Image.FromFile(Text);
System.IO.MemoryStream ms = new System.IO.MemoryStream();
img.Save(ms, System.Drawing.Imaging.ImageFormat.Bmp);
ConnectionClass connection = new ConnectionClass();
DataTable data_table = connection.queryMethod("insert into USER values(Scheme =@Scheme)");
//А как дальше изменить не пойму

  openFileDialog1.ShowDialog();
                pictureBox1.ImageLocation = openFileDialog1.FileName;
                this.Text = openFileDialog1.FileName;
 
                System.Drawing.Image img = System.Drawing.Image.FromFile(Text);
                System.IO.MemoryStream ms = new System.IO.MemoryStream();
                img.Save(ms, System.Drawing.Imaging.ImageFormat.Bmp);
 
                ConnectionClass connection = new ConnectionClass();
                DataTable datatable = connection .queryMethod("INSERT INTO USER values (image=@Scheme)");
 
                datatable.Parameters.Add("@Scheme", SqlDbType.Image).Value = ms.ToArray();

comm.Parameters.Add("@Scheme", SqlDbType.Image).Value = ms.ToArray();