Как найти максимум и минимум в дубликатах

let allC = [
    {nameCoin:"NEAR",price:5.036,"link":"https://www.bybit.com/trade/usdt/NEARUSDT"},
    {nameCoin:"NEAR",price:5.034,"link":"https://www.gate.io/ru/futures/USDT/NEAR_USDT"},
    {nameCoin:"NEAR",price:5.037,"link":"https://www.okx.com/ru/trade-swap/near-usdt-swap"},
    {nameCoin:"XRP",price:0.4902,"link":"https://www.okx.com/ru/trade-swap/xrp-usdt-swap"},
    {nameCoin:"XRP",price:0.4899,"link":"https://www.bybit.com/trade/usdt/XRPUSDT"},
    {nameCoin:"XRP",price:0.4901,"link":"https://www.gate.io/ru/futures/USDT/XRP_USDT"},
    {nameCoin:"TON",price:7.092,"link":"https://www.okx.com/ru/trade-swap/ton-usdt-swap"},
    {nameCoin:"TON",price:7.0839,"link":"https://www.bybit.com/trade/usdt/TONUSDT"},
    {nameCoin:"TON",price:7.0857,"link":"https://www.gate.io/ru/futures/USDT/TON_USDT"},
    {nameCoin:"TOKEN",price:0.08423,"link":"https://www.gate.io/ru/futures/USDT/TOKEN_USDT"},
    {nameCoin:"TNSR",price:0.613,"link":"https://www.gate.io/ru/futures/USDT/TNSR_USDT"}
]
 
const dub = []
 
for (let i = 0; i < allC.length; i++) {
    for (let j = i + 1; j < allC.length; j++){
        if(allC[i].nameCoin === allC[j].nameCoin){
            dub.push(allC[i])
        }
    }
}

const a = [
    {nameCoin:"NEAR",price:5.036},
    {nameCoin:"NEAR",price:5.034},
    {nameCoin:"NEAR",price:5.037},
    {nameCoin:"XRP",price:0.4902},
    {nameCoin:"XRP",price:0.4899},
    {nameCoin:"XRP",price:0.4901},
    {nameCoin:"TON",price:7.092},
    {nameCoin:"TON",price:7.0839},
    {nameCoin:"TON",price:7.0857},
    {nameCoin:"TOKEN",price:0.08423},
    {nameCoin:"TNSR",price:0.613}
]
const val = (m , o) => {
    if (!m.has(o.nameCoin)) return [o, o]
    const v = m.get(o.nameCoin)
    if (o.price < v[0].price) v[0] = o
    if (o.price > v[1].price) v[1] = o
    return v
}
const f = (m, o) => {
    const v = val(m, o)
    m.set(o.nameCoin, v)
    return m
}
const m = a.reduce(f, new Map())
console.log(m)