Вычислить выражение по формуле - Assembler - Ответ 3113355

#include "stdafx.h"
#include <iostream>
#include <conio.h>
using namespace std;
float a, b, c, d, e, x, y, s;
void main ()
{
cout << " Enter A "; cin >> b; if (!cin) {cout << "ERROR! Nepravilnoe znachenie; Programma zavershaetsa!!!! Press Enter" << endl; getch();}
cout << " Enter B "; cin >> b; if (!cin) {cout << "ERROR! Nepravilnoe znachenie; Programma zavershaetsa!!!! Press Enter" << endl; getch();}
cout << " Enter C "; cin >> c; if (!cin) {cout << "ERROR! Nepravilnoe znachenie; Programma zavershaetsa!!!! Press Enter" << endl; getch();}
cout << " Enter D "; cin >> d; if (!cin) {cout << "ERROR! Nepravilnoe znachenie; Programma zavershaetsa!!!! Press Enter" << endl; getch();}
cout << " Enter E "; cin >> e; if (!cin) {cout << "ERROR! Nepravilnoe znachenie; Programma zavershaetsa!!!! Press Enter" << endl; getch();}
cout << " Enter X "; cin >> x; if (!cin) {cout << "ERROR! Nepravilnoe znachenie; Programma zavershaetsa!!!! Press Enter" << endl; getch();}
cout << " Enter Y "; cin >> y; if (!cin) {cout << "ERROR! Nepravilnoe znachenie; Programma zavershaetsa!!!! Press Enter" << endl; getch();}
s=(a*x*x*y*y+b*x*y*y*y+c*y*y)+(d*x)+(e*y)+a;
cout << "Otvet na C++: " << s << endl;
__asm
{
mov  eax, a
imul x 
imul x
imul y
imul y
mov ebx, b 
imul ebx, x 
imul ebx, y 
imul ebx, y
imul ebx, y
add eax, ebx 
mov ebx, c 
imul ebx, y 
imul ebx, y 
add eax, ebx 
mov ebx, d 
imul ebx, x 
add eax, ebx 
mov ebx, e
imul ebx, y 
add eax, a
add ebx, eax 
mov s, ebx 
}
cout << "Podschet okonchen; otvet:";
cout << s << endl;
cout << "Press Enter";
getch();
}