Найти числа, которые присутствуют подряд в 5-8 строках

table = [eval(line) for line in open('result.txt')]
 
width = 20
longest_repeat = {}
 
for i in range(width):
    curr_obj = table[0][i]
    repeat_number = 1
    for line in table[1:]:
        if curr_obj == line[i]:
            repeat_number += 1
        else:
            if longest_repeat.get(curr_obj, 0) < repeat_number:
                longest_repeat[curr_obj] = repeat_number
            curr_obj = line[i]
            repeat_number = 1
 
print(longest_repeat)

import itertools
import re
import os
from collections import deque
 
with open("result.txt") as f:
    for row_txt in deque(f, 50):
        row_lst = [int(x) for x in re.findall('\d+', row_txt)]
        a = [[0] * len(row_lst) for b in range(81)]
        for i, row in enumerate(row_lst):
            for j in row:
                a[j][i] = 1
            # print(*enumerate(a), sep='\n')
 
    for i, row in enumerate(a):
        k = max_k = 1
        for j in range(1, len(row)):
            if row[j - 1] + row[j] == 2:
                k += 1
            else:
                max_k = max(max_k, k)
                k = 1
        if max_k > 1:
            print(i, 'залипла.', max_k, 'раз')

import re
lst = []
myfile = open("result.txt", 'r')
for row in myfile:
    lst.append([int(x) for x in re.findall('\d+', row)])
 
a = [[0]*len(lst) for _ in range(81)]
for i, row in enumerate(lst):
    for j in row:
        a[j][i] = 1
# print(*enumerate(a), sep='\n')
 
for i, row in enumerate(a):
    k = max_k = 1
    for j in range(1, len(row)):
        if row[j-1] + row[j] == 2:
            k += 1
        else:
            max_k = max(max_k, k)
            k = 1
    if max_k > 1:
        print(i, 'залипла.', max_k, 'раз')

table = [eval(line) for line in open('result.txt')]
longest_repeat = {}
 
for n in range(1, 81):
    occur_count = 0
    for line in table:
        if n in line:
            occur_count += 1
        else:
            if occur_count > 1:
                longest_repeat[n] = max(longest_repeat.get(n, 0), occur_count)
            occur_count = 0
 
print(longest_repeat)

from itertools import groupby
 
table = [eval(line) for line in open('result.txt')]
longest_repeat = {}
 
for n in range(1, 81):
    contains_groups = groupby(n in line for line in table)
    longest = max(sum(1 for _ in seq) for k, seq in contains_groups if k)
    if longest > 1:
        longest_repeat[n] = longest
 
print(longest_repeat)