Метод format

D = dict (name='Bob' , job='dev')
'{0 [name]} {0 [job]} {0 [name]}'. format (D)

{0 [job]}

{1 [job]}

'{0}, {1}, {2}'

 str.format(*args, **kwargs) -> str 
 
args - Позиционные аргументы.
 
kwargs - Именованные аргументы.

>>> D = dict (name='Bob' , job='dev')
>>> '{name} {job} {name}'. format (**D)
'Bob dev Bob'

>>> empl={'name':'Bob', 'job':'manager'}
>>> print(f'{empl["name"]} {empl["job"]}')
Bob manager

dict (name='Bob' , job='dev')

'{0 [name]} {0 [job]} {0 [name]}'. format (D)

>>> '{0}, {1}, {2}'.format(1,2,3)
'1, 2, 3'
>>> '{}, {}, {}'.format(1,2,3)
'1, 2, 3'
>>> '{one}, {two}, {three}'.format(one=1,two=2,three=3)
'1, 2, 3'
>>> class Number:
    one = 1
    two = 2
    three = 3
 
    
>>> '{0.one}, {1.two}, {2.three}'.format(Number(), Number(),Number())
'1, 2, 3'
>>>

all_.append(f'{razdel_num}, {glava_num}, {statja_num}')

all_.append(f'{razdel_num=}, {glava_num=}, {statja_num=}')
print(f'{all_[0]=}')

val.split(f'{chr(39)}')[-2]

>>> D = dict(name='Bob', job='dev')
>>> '{0[name]} {0[job]} {0[name]}'.format(D)
'Bob dev Bob'

>>> D = dict(name='Bob', job='dev')
>>> '{0[name]} {0[job]} {0[name]}'.format(D)
'Bob dev Bob'

D = dict(name='Bob', job='dev')

T = tuple(name='Bob', job='dev')

>>> T = tuple(name='Bob', job='dev')
Traceback (most recent call last):
  File "<pyshell#8>", line 1, in <module>
    T = tuple(name='Bob', job='dev')
TypeError: tuple() takes no keyword arguments

>>> D = dict(name='Bob', job='dev')
>>> D1 = dict(name='Bob1', job='dev1')
>>> D2 = dict(name='Bob2', job='dev2')
>>> '{0[name]} {1[job]} {2[name]}'.format(D, D1, D2)
'Bob dev1 Bob2'
>>>