Любой исправный парсер сайта с уведомлениями в Телеграм

import telebot
import requests
from bs4 import BeautifulSoup as bs4
 
bot = telebot.TeleBot('5340841914:AAF38uCuhT8bSg2Srv4Bm7So4Jlf_dyYv4s')
 
def get_data():
    # парсер
    url = 'https://draft.dev/learn/python-blogs'
    r = requests.get(url)
    soup = bs4(r.text, "html.parser")
    langs = soup.select('h3>a')
    return '\n'.join(f'<a href="{x.attrs.get("href")}">{x.text}</a>' for x in langs)
 
@bot.message_handler(commands=['get_lang'])
def greets(message):
    # бот, который использует парсер
    langs = get_data()
    bot.send_message(message.chat.id, langs, parse_mode='HTML', disable_web_page_preview=True)
 
if __name__ == "__main__":
    bot.infinity_polling()

pip uninstall telebot pyTelegramBotAPI
pip install pyTelegramBotAPI

import requests
from bs4 import BeautifulSoup
 
url = 'https://funpay.com/lots/148/'
response = requests.get(url)
soup = BeautifulSoup(response.text, 'lxml')
items = soup.find_all('a', class_='tc-item')
 
for n, i in enumerate(items, start=1):
    itemName = i.find('div', class_='tc-desc').text.strip()
    itemPrice = i.find('div', class_='tc-price').text.strip()
    print(f'{n}:  {itemPrice} за {itemName}')