Найти все пары натуральных дружественных чисел, меньших 10 000

number = 1
number_2 = 1
counter = 0
counter_2 = 0
for i in range(1, 10000):
    number = i - 1
    while number > 0:
        if i % number == 0:
            counter += number
            number -= 1
        else:
            number -= 1
    number_2 = counter - 1
    while counter > 0 and number_2 != 0:
        if counter % number_2 == 0:
            counter_2 += number_2
            number_2 -= 1
        else:
            number_2 -= 1
    if i == counter_2 and i < counter:
        print(i, counter)
    counter = 0
    counter_2 = 0

def fun(num):
    res = 1
    d = 2
    while d*d <= num:
        if num%d == 0:
            res += d + num//d*(d*d != num)
        d += 1
    return res 
 
 
lst = []
for i in range(1, 10000 + 1):
    k = fun(i)
    if i < k <= 10000 and fun(k) == i:
        lst.append((i,k))
for i in lst:
    print(*i)

e, f = 0, 0
for i in range(1, 10000):
    a, b = 0, 0
    for k in range(1, i):
        if i % k == 0:
            b += k
    for j in range(1, b):
        if b % j == 0:
            a += j
    if i == a and b and a and i != b and f != i and e != b:
        e, f = i, b
        print(i, b)