Подсчитать число элементов массива, у которых вторая с конца цифра - чётная

lst = [rd.randint(1000, 2000) for i in range(10)]
count = 0
for number in lst:
    if int(str(number)[2]) % 2 == 0:
        count += 1
 
print(lst)
print(count)

from random import randint
 
lst = [randint(1000, 2000) for i in range(10)]
count = 0
for number in lst:
    if ((number % 100) // 10) % 2 == 0:
        count += 1
 
print(lst)
print(count)

from random import randint
lst = [randint(1000, 2000) for i in range(10)]
print(lst)
print(sum(~i//10%2 for i in lst))

from re import findall
from random import randint
 
lst = [randint(1000, 2000) for i in range(10)]
print(len(findall(r'\D\d*[24680]\d\D', str(lst))))

l = [1122, 3312, 2233, 6714, 5115, 5116, 7711, 8598]
print(len(list(filter(lambda x: not x % 100 // 10 % 2, l))))

lst=[1122, 3312, 2233, 6714, 5115, 5116, 7711, 8585]
print(len([1 for x in lst if x >= 100 and (x//10)%10 in (0,2,4,6,8)]))

print(len(list(filter(lambda x: not abs(x) % 100 // 10 % 2, l))))

import sys
def main_func(arg):
    result = 0
    for line in arg:
        result =+ len(list(filter(lambda x: not abs(x) % 100 // 10 % 2, map(int, line.split()))))
    return result
 
data = sys.stdin.readlines()
print(main_func(data))

x = list(map(int, input().split()))
print(sum(map(lambda x: x // 10 % 2 == 0, x)))

foo = lambda x: not x % 2
print(len([el for el in input().split() if foo(int(el)//10 % 10)]))

def get_cnt_nums(*nums):
    return sum(1 for n in nums if ((n // 10) % 10) % 2 == 0)
 
nbr = map(lambda s: abs(int(s)), input().split())
print(get_cnt_nums(*nbr))

def get_cnt_nums(*nums):
    return len(nums) - sum(1 for n in nums if ((n // 10) % 10) % 2)
 
nbr = map(lambda s: abs(int(s)), input().split())
print(get_cnt_nums(*nbr))