Определите и запишите в ответе сначала количество пар элементов последовательности, в которых чётность чисел различна, п

file = open("17.txt")
a = [int(x) for x in file]
zero = []
for i in range(len(a)):
    if a[i] % 2 == 0 and a[i - 1] % 2 != 0:
        if a[i] % 4 == 0 and a[i - 1] % 11 == 0:
            zero.append(a[i] + a[i - 1])
print(len(zero), max(zero))

if a[i] % 2 == 0 and a[i - 1] % 2 != 0:

with open("17.txt", 'r') as file:
    a = list(map(int, file.read().splitlines()))
    print(a)
 
zero = []
for i in range(len(a) - 1):
    if a[i] % 2 != a[i + 1] % 2 and (a[i] % 4 == 0 and a[i + 1] % 11 == 0 or a[i] % 11 == 0 and a[i + 1] % 4 == 0):
        zero.append(a[i] + a[i + 1])
print(len(zero), max(zero))

with open("17.txt", 'r') as file:
    a = list(map(int, file.read().splitlines()))
    print(a)
 
zero = []
for i in range(len(a) - 1):
    if (a[i] % 2 == 0 and a[i + 1] % 2 == 1 and a[i] % 4 == 0 and a[i + 1] % 11 == 0) or (
            a[i] % 2 == 1 and a[i + 1] % 2 == 0 and a[i] % 11 == 0 and a[i + 1] % 4 == 0):
        zero.append(a[i] + a[i + 1])
print(len(zero), max(zero))

...
for i in range(len(a)-1):
    if (a[i] + a[i-1])%2:
        even, odd = a[i], a[i-1]        
        if a[i]%2 :
            even, odd = a[i-1], a[i]        
        if even % 4 == 0 and odd % 11 == 0:
            zero.append(a[i] + a[i - 1])
...